45x^2-500=0

Solution for 45x^2-500=0 equation:

45x^2-500=0

a = 45; b = 0; c = -500;
Δ = b2-4ac
Δ = 02-4·45·(-500)
Δ = 90000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{90000}=300$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-300}{2*45}=\frac{-300}{90}
=-3+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+300}{2*45}=\frac{300}{90}
=3+1/3
$